MCQ practice · SSC Higher Mathematics Board questions · Chapter 6: Inequality
Which is the solution set of the inequality 4x + 3 > 19?
Think it through first, then pick an option.
- a S = {x ∈ R : x > 4}
- b S = {x ∈ R : x < 4}
- c S = {x ∈ R : x ≤ 4}
- d S = {x ∈ R : x ≥ 4}
Answer and explanation
Correct answer: a S = {x ∈ R : x > 4}
4x > 16 and 4 is positive, so x > 4; the sign is strict, so 4 is not in the set.
Why the other options are wrong
- b S = {x ∈ R : x < 4}: Dividing by the positive 4 does not reverse the direction; 4x > 16 gives x > 4.
- c S = {x ∈ R : x ≤ 4}: Both direction and sign are wrong: the original sign is > (no equality) and the result is x > 4.
- d S = {x ∈ R : x ≥ 4}: The direction is right, but the original sign > has no equality, so x = 4 is not in the set: x > 4.
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