Higher Mathematics · Classes 9-10 · Chapter 1
One-One Correspondence, Equivalent Sets, Intervals, and Finite and Infinite Sets.
Every person in a hall is sitting on exactly one chair, and no chair is empty. Without counting anyone you can say the people and the chairs are equal in number. Mathematics turns this pairing into an idea deeper than counting, and it can even measure infinite sets.
1. One-one correspondence
Suppose each element of A can be matched with one and only one element of B, and each element of B with one and only one element of A. Then there is a one-one correspondence between A and B, written A ↔ B. When x is matched with y we write x ↔ y.
A = {a, b, c} is a set of three persons and B = {30, 40, 50} the set of their ages. a ↔ 30, b ↔ 40, c ↔ 50 is a one-one correspondence. Draw matches yourself below: pick an element, then one on the other side.
Build a one-one correspondence
Drawn by hand, not to scale. Nothing here goes anywhere. The page is yours.
2. Equivalent sets
If a one-one correspondence A ↔ B can be described between two sets A and B, they are called equivalent sets, written A ∼ B.
Three facts hold for any sets A, B, C. Proposition 4: A ∼ A, because every x can be matched with itself, x ↔ x. If A ∼ B then B ∼ A. Proposition 5: if A ∼ B and B ∼ C then A ∼ C, since the matches link up like a chain x ↔ y ↔ z. The empty set is taken as equivalent to itself, ∅ ∼ ∅.
Example 13: {1, 2, 3, ···, n} and {1, 3, 5, ···, 2n − 1} are equivalent. The rule is k ↔ 2k − 1.
Example 14: the natural numbers N and the even numbers {2, 4, 6, ···, 2n, ···} are equivalent. The rule is n ↔ 2n.
Equal and equivalent are not the same thing. Equal sets have exactly the same elements. Equivalent sets only need a one-one correspondence. So {1, 2, 3} ∼ {a, b, c}, but {1, 2, 3} ≠ {a, b, c}. For finite sets, n(A) = n(B) is enough for A ∼ B.
3. Intervals
For real numbers a and b with a < b there are four kinds of interval:
(a, b) = {x ∈ R : a < x < b}, an open interval;
[a, b] = {x ∈ R : a ≤ x ≤ b}, a closed interval;
(a, b] = {x ∈ R : a < x ≤ b}, an open-closed interval;
[a, b) = {x ∈ R : a ≤ x < b}, a closed-open interval.
Draw an interval on the number line yourself. Slide a and b, decide whether each end is in, and watch the notation write itself.
A filled dot is [, a hollow one is (
The line is drawn by hand, not to scale. The ends stop on whole numbers here, but a and b may be any real numbers.
Read the brackets against the condition: {x ∈ R : −3 ≤ x < 3} = [−3, 3) and {x ∈ R : 1 ≤ x ≤ 7} = [1, 7]. “[” means the end number is included, “(” means it is left out. ≤ means [, < means (.
Which interval?
4. Finite and infinite sets
A set whose number of elements can be fixed by counting is a finite set. A set that is not finite is an infinite set. Matching A = {15, 16, ···, 22} with {1, 2, ···, 8} gives 8 elements.
The empty set ∅ is finite with 0 elements. If A ∼ Jₘ = {1, 2, ···, m}, then A is finite with m elements. The number of elements of a finite set A is written n(A), and writing n(A) means A is finite.
If A and B are equivalent and one of them is finite, the other is finite too, and n(A) = n(B).
Proposition 6: if A is finite and B is a proper subset of A, then B is finite and n(B) < n(A). So a finite set can never be equivalent to a proper part of itself.
Proposition 7: A is infinite if and only if A is equivalent to one of its proper subsets. The set of natural numbers N is infinite.
See Propositions 6 and 7 in a hotel. Every room has one guest. One rule: the guest in room n moves to room 2n. What happens in a finite hall, and in an endless hotel?
n ↔ 2n: is anyone left out?
The hotel is a story and is not in the book. The rule n ↔ 2n is the book's Example 14.
There is one way to show a set is infinite: choose a proper subset and show a one-one correspondence with it. The odd numbers {1, 3, 5, ···} and the proper subset {3, 5, 7, ···}, matched by k ↔ k + 2. The squares {1, 4, 9, ···} and {4, 9, 16, ···}, matched by n² ↔ (n + 1)².
Activity and Exercise 12: {1, 2, ···, n} ∼ {1, 2, 2², ···, 2ⁿ⁻¹} through k ↔ 2ᵏ⁻¹. S = {3ⁿ : n = 0 or n ∈ N} = {1, 3, 9, ···} ∼ N through n ↔ 3ⁿ⁻¹. And the proper subset {1, 9, 81, ···} = {3²ⁿ} of S is equivalent to S through 3ⁿ ↔ 3²ⁿ. Tap the four rows to see it.
Matching an infinite set
| set | proper subset | match |
|---|---|---|
| {1, 2, 3, ···} | {2, 4, 6, ···} | n ↔ 2n |
| {1, 3, 5, ···} | {3, 5, 7, ···} | k ↔ k + 2 |
| {1, 4, 9, ···} | {4, 9, 16, ···} | n² ↔ (n + 1)² |
| {1, 3, 9, ···} | {1, 9, 81, ···} | 3ⁿ ↔ 3²ⁿ |
5. Counting every correspondence
Between A = {a, b} and B = {1, 2} there are two one-one correspondences: a ↔ 1, b ↔ 2 and a ↔ 2, b ↔ 1. For two sets of three elements there are 3 × 2 × 1 = 6. Each can be written as the set of ordered pairs F = {(x, y) : x ∈ A, y ∈ B, x ↔ y}, such as {(a, 1), (b, 2)}. The builder above shows these pairs once your matching is complete.
6. Check yourself
Three questions; if you miss one, go back to the note.
Question 1
Which of these is an infinite set?
Read the second one, think, then tap.
Question 2
A correspondence n ↔ 2n is drawn between N = {1, 2, 3, ···, n, ···} and A = {2, 4, 6, ···, 2n, ···}. How are N and A related?
The last question.
Question 3
If n(A) = n(B), which of these statements are correct?
i. A and B are finite sets
ii. A and B have the same number of subsets
iii. A and B are equivalent sets
The whole note on seven cards.
Seven cards
Source: Higher Mathematics, Classes 9-10 (NCTB), Chapter 1 “Set and Function”, the “One-One Correspondence, Equivalent Sets, Intervals, and Finite and Infinite Sets” part.