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MCQ practice · SSC Physics Board questions · Chapter 1: Physical Quantities and Their Measurements

Jashore Board 2021

To find the thickness of a rectangular glass slab with a slide calipers, the main-scale reading is 18 mm and the vernier coincidence is 8. If the vernier constant of the instrument is 0.01 cm, what is the thickness?

Think it through first, then pick an option.

  1. a 8.1 mm
  2. b 8.18 mm
  3. c 18.08 mm
  4. d 18.8 mm
Answer and explanation

Correct answer: d 18.8 mm

The constant 0.01 cm = 0.1 mm; thickness = 18 mm + 8 × 0.1 mm = 18.8 mm.

Why the other options are wrong

  • a 8.1 mm: 8.1 mm is wrong; the main-scale reading 18 mm is missing, and 8 × 0.1 mm = 0.8 mm.
  • b 8.18 mm: 8.18 mm is wrong; the thickness exceeds 18 mm because the main-scale reading alone is 18 mm.
  • c 18.08 mm: 18.08 mm is wrong; the constant 0.01 cm = 0.1 mm, not 0.01 mm, so 8 × 0.1 = 0.8 mm is added.