MCQ practice · SSC Physics Board questions · Chapter 1: Physical Quantities and Their Measurements
The least count of a screw gauge of pitch 2 mm is 0.002 cm. What is the number of divisions of the circular scale?
Think it through first, then pick an option.
- a 10³
- b 10²
- c 10⁻²
- d 10⁻³
Answer and explanation
Correct answer: b 10²
0.002 cm = 0.02 mm; number of divisions = pitch ÷ least count = 2 ÷ 0.02 = 100 = 10².
Why the other options are wrong
- a 10³: 1000 divisions would give a least count of 2 mm ÷ 1000 = 0.002 mm; here 0.002 cm = 0.02 mm.
- c 10⁻²: 10⁻² = 0.01 cannot be a number of divisions; divisions = pitch ÷ least count = 100.
- d 10⁻³: 10⁻³ = 0.001 cannot be a number of divisions; divisions = pitch ÷ least count = 100.
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