MCQ practice · SSC Chemistry Board questions · Chapter 7: Chemical Reactions
The compound B in the stem-
- i. aqueous solution is acidic
- ii. oxidation number of the central atom is +4
- iii. the octet rule is broken in it
Think it through first, then pick an option.
- a i and ii
- b ii and iii
- c i and iii
- d i, ii and iii
Answer and explanation
Correct answer: c i and iii
B = SO₃: it dissolves to give H₂SO₄, so the solution is acidic (i). S is +6, so ii is false. Sulphur holds 12 electrons, an exception to the octet rule (iii).
Why the other options are wrong
- a i and ii: i is true but ii is false: in B = SO₃ sulphur is +6, not +4. iii is left out: SO₃ breaks the octet rule.
- b ii and iii: ii is false: S + O₂ → SO₂ (A), SO₂ + O₂ → SO₃ (B). In SO₃, x + 3(−2) = 0 gives x = +6; +4 is the value in SO₂. And i is true, so it cannot be left out.
- d i, ii and iii: ii is not true: in B = SO₃ sulphur is +6. The +4 belongs to A = SO₂. So not all three are true.
More board questions on this topic
- What is the oxidation number of hydrogen in CaH₂?
- What is the oxidation number of hydrogen in LiAlH₄?
- What is the oxidation number of oxygen in a peroxide compound?
- What is the oxidation number of oxygen in NaO₂?
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