MCQ practice · SSC Chemistry Board questions · Chapter 7: Chemical Reactions
In the case of the stem-
- i. Y is the most electronegative element
- ii. Z²⁺ acts as both oxidant and reductant
- iii. X reacts with dilute H₂SO₄
Think it through first, then pick an option.
- a i and ii
- b i and iii
- c ii and iii
- d i, ii and iii
Answer and explanation
Correct answer: a i and ii
iii is false: X = Cu (29 protons) sits below H in the activity series, so it does not react with dilute H₂SO₄. i and ii are true: Y = F is the most electronegative; Z = Fe, and Fe²⁺ is both oxidant and reductant.
Why the other options are wrong
- b i and iii: i is left out: Y = F (atomic number 9), the most electronegative element. And iii is false: Cu does not react with dilute H₂SO₄.
- c ii and iii: ii is left out: Z = Fe (it rusts), and Fe²⁺ → Fe³⁺ + e⁻ and Fe²⁺ + 2e⁻ → Fe, so it is both oxidant and reductant. And iii is false: Cu does not react with dilute H₂SO₄.
- d i, ii and iii: iii is false: X = Cu sits below H in the activity series, so it does not react with dilute H₂SO₄.
More board questions on this topic
- Which is oxidized in the reaction Ca + Cl₂ → CaCl₂?
- In Mg + ZnSO₄ → MgSO₄ + Zn, which is oxidized?
- In Sn⁴⁺ + Fe²⁺ → Sn²⁺ + Fe³⁺, which is reduced?
- SnCl₂ + 2FeCl₃ → 2FeCl₂ + SnCl₄. In the reaction in the stem-
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