MCQ practice · SSC Chemistry Board questions · Chapter 6: Concept of Mole and Chemical Counting
What is compound 'A'?
Think it through first, then pick an option.
- a CH₃CH₂CH₂OH
- b CH₃CH₂CHO
- c CH₃COOH
- d CH₃CH₂OCH₃
Answer and explanation
Correct answer: a CH₃CH₂CH₂OH
C = 60/12 = 5, H = 13.33, O = 26.67/16 = 1.67, ratio 3 : 8 : 1, so C₃H₈O (mass 60), and it is an alcohol, which oxidises.
Why the other options are wrong
- b CH₃CH₂CHO: This is C₃H₆O (mass 58); the calculation gives C₃H₈O.
- c CH₃COOH: This is C₂H₄O₂ (mass 60), but it has 40% C; here C is 60%.
- d CH₃CH₂OCH₃: Its formula is also C₃H₈O, so the numbers cannot tell them apart; but an ether is not oxidised by H₂SO₄ and K₂Cr₂O₇, and the stimulus says oxidation gives B.
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