MCQ practice · SSC Chemistry Board questions · Chapter 6: Concept of Mole and Chemical Counting
What is the mass of solute in a semimolar solution of 'sodium carbonate'?
Think it through first, then pick an option.
- a 10.6 grams
- b 26.5 grams
- c 53 grams
- d 106 grams
Answer and explanation
Correct answer: c 53 grams
Semimolar = 0.5 mole per liter; Na₂CO₃ = 106, so 0.5 × 106 = 53 grams.
Why the other options are wrong
- a 10.6 grams: 10.6 grams is the solute in 1 liter of decimolar; semimolar holds 0.5 × 106 = 53 grams.
- b 26.5 grams: 26.5 grams is 0.25 mole; semimolar has 0.5 mole per liter = 53 grams.
- d 106 grams: 106 grams is 1 mole, the solute in a 1 M solution; semimolar holds 53 grams.
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